TEST D'ÉVALUATION DE NIVEAU - CSRS

MATHÉMATIQUES ... 9) 51,49. + 21,019. 72,509. 10) 2,12. x ? 1,05. 1060. 000.
212. -2,2260. 11) ?89 ?17 ... C) 3 x 2,25 $ + 2 x 10 $ + 25 $ + 35 $ = 86,75 $.

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Corrigé du dérouillage pré-diagnostique
MATHÉMATIQUES SECONDAIRE I MAT 1005
MAT 1006
MAT 1007 SECONDAIRE II MAT 2006
MAT 2007 SECONDAIRE III MAT 3001 MAT 3002
MAT 3003 CLÉ DE CORRECTION Concepteurs : Mario Dumais,
Gilles Dulac et Eric Malenfant
Décembre 2009 Secondaire 1 |2 |-10 |3) 40 |4) -6 |
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|[pic][pic] |6) [pic] |
| |8) |
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| 51,49 | 2,12 |
|+ 21,019 |x - 1,05 |
|72,509 |1060 |
| |000 |
| |212 |
| |-2,2260 |
|-89 -17 |12) |
|5,23... | |
|40 | |
|- 34 | |
|60 | |
|- 51 | |
|9... | |
|3 ( 5 = 0,6 |14) |
|0,6 + 1,9 = | |
|2,5 | |
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|[pic] ; [pic] ; | |
| |18) |
|1 ( 25 = 0,04 | |
|0,04 x 100 = 4% | |
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|2 + 3 x 2 - 4 |3 - 5 [(-3 - 9) - (-12 ( 3)]= |
|2 + 6 - 4 |3 - 5 [(-12) - (-4)]= |
|8 - 4 |3 - 5 x [-8]= |
|= 4 |3 + 40 = |
| |43 |
| |23) | |
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|24) A) 3 + 2 + 1 + 1 = 7 |
|Il a acheté 7 morceaux. |
|2,25 $ |
|x 3 |
|6,75 $ |
|6,75 $ pour 3 paires de bas. |
|C) 3 x 2,25 $ + 2 x 10 $ + 25 $ + 35 $ = 86,75 $ |
|La facture totale est de 86,75 $. |
|D) |
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|Il lui reste 28,92 $ à payer. |
|E) |
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|Le prix du pantalon sera de 29,75 $. |
|F) |
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|Le prix moyen d'un article est 12,39 $. | Secondaire 2
|-3x + 5 = -4 |x + 4x - 5 ( 7 - 2x + 8 |
|-3x = -4 - 5 |x + 4x + 2x ( 7 + 8 + 5 |
|-3x = -9 |7x ( 20 |
|x = -9 ( -3 |x ( [pic] ou [pic] |
|x = 3 | |
|-7 -[pic]x = 3x + 5 |-3x + 7x ( 5x + 8 |
|-[pic]x - 3x = 5 + 7 |-3x + 7x - 5x ( 8 |
|-[pic]x - [pic]x = 12 |-1x ( 8 |
|-[pic]x = 12 |x ( 8 ( -1 |
|x = [pic] ( -[pic] |x ( -8 |
|x = [pic] ( -[pic] | |
|x = -[pic] ou -[pic] | |
|3(2x - 5) + 4 = 3x + 7 |A = bh |
|6x - 15 + 4 = 3x + 7 |128 = 4h |
|6x - 3x = 7 + 15 - 4 |128 ( 4 = h |
|3x = 18 |32 = h |
|x = 18 ( 3 | |
|x = 6 | |
|6x - 5 < 3x + 2 |P = 2 (L + k ) | |
|6x - 3x < 2 + 5 |72 = 2 (L + 13) |46 = 2L |
|3x < 7 |72 = 2L +26 |46 ( 2 = L |
|x < [pic] ou [pic] |72 - 26 = 2L |23 = L |
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|24 x 9 = 5x |9 (3x+1) = 12 (x+2) |
|216 = 5x |27x + 9 = 12x + 24 |
|216 ( 5 = x |27x - 12x = 24 - 9 |
|43,2 = x |15x = 15 |
| |x = 15 ( 15 |
| |x = 1 |
|4 (x + 6) = 7 (2x - 5) |14x = 15 (x + 4) |
|4x + 24 = 14x - 35 |14x = 15x + 60 |
|4x - 14x = -35 - 24 |14x - 15 x = 60 |
|-10x = -59 |-1x = 60 |
|x = -59 ( -10 |x = 60 ( -1 |
|x = 5,9 |x = -60 |
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|12 pommes = 2,99$ |2,99 x = 12 x 6,50 |
|x pommes = 6,50$ |2,99 x = 78 |
| |x = 78 ( 2,99 |
| |x = 26,09 donc 26 pommes |
|3 oranges = 12 portions | |
|x oranges = 50 portions |par le même raisonnement on |
| |obtiendra : |
|12 x = 3 x 50 | |
|12 x = 150 |20,8 donc 21 clémentines |
|x = 150 ( 12 |2,08 donc 2 melons |
|x = 12,5 donc 13 oranges |12,5 donc 13 pommes et |
| |4,17 donc 4 mangues |
|x = l'âge de la fille |3x + 21 = x + 27 |La fille a 3 ans |
|x + 20 = âge de la mère |3x - x = 27 - 21 |La mère, 23 ans. |
|donc : |2x = 6 | |
|3 (x + 7) = (x + 20) + 7 |x = 3 | |
|x = le premier n