Answers Exam 2004-2005
(d) Let x be the length of AD and 2 = BAC. Then cos = 3/x and 3/5 = cos 2 = 2
cos2 - 1 = 18/x2 ? 1 which gives x = 3/2. 26. (e) 1/log 2 + 1/log 4 = 1/log 2 + ...
(d) Let x be the length of AD and 2 = BAC. Then cos = 3/x and 3/5 = cos 2 = 2
cos2 - 1 = 18/x2 ? 1 which gives x = 3/2. 26. (e) 1/log 2 + 1/log 4 = 1/log 2 + ...